Key Concepts & Self-Assessment20 Key Facts
Review key What Is Terminal Velocity? Fluid Drag Force, Gravitational Equilibrium & Parachute Physics exam facts and rate your mastery to track revision.
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#1
Terminal velocity is the constant speed reached by a falling body when the upward fluid drag and buoyant forces balance the downward force of gravity.
#2
At terminal velocity, the net external force acting on the falling object is zero according to Newton's First and Second Laws of Motion.
#3
Because the net force equals zero at terminal velocity, the object's downward acceleration drops to zero meters per second squared.
#4
For macroscopic objects in turbulent air, aerodynamic drag is modeled by the drag equation: Fd = 0.5 rho v² Cd A.
#5
In the high-speed drag equation, rho is fluid density, v is velocity, Cd is the drag coefficient, and A is the projected frontal cross-sectional area.
#6
The terminal velocity formula for turbulent flow is vt = sqrt((2 m g) / (rho Cd A)), where m is mass and g is gravitational acceleration.
#7
Increasing the frontal area (A) or drag coefficient (Cd) decreases terminal velocity, which explains why parachutes slow descents.
#8
Increasing the object's mass (m) increases terminal velocity, meaning heavier objects of identical size and shape fall faster through air.
#9
For small spherical particles moving at low Reynolds numbers, Stokes' Law defines viscous drag as Fd = 6 pi eta r v.
#10
In Stokes' Law, eta represents the dynamic viscosity of the fluid, r is the radius of the spherical particle, and v is velocity.
#11
Under Stokes' Law, terminal velocity is directly proportional to the square of the particle radius: vt = (2/9) r² (rhop - rhof) * g / eta.
#12
A typical skydiver falling belly-to-earth with spread limbs reaches a terminal velocity of roughly 54 m/s (approximately 195 km/h).
#13
A skydiver in a streamlined head-first dive minimizes frontal area, increasing terminal velocity to over 90 m/s (roughly 324 km/h).
#14
An open parachute increases cross-sectional area to reduce terminal velocity to a safe landing speed of about 5 to 6 m/s.
#15
Typical cloud raindrops attain terminal velocities ranging from 2 m/s for small drizzle droplets to 9 m/s for large raindrops.
#16
Without atmospheric drag, raindrops falling from 2,000 meters altitude would accelerate to over 700 km/h, causing severe surface destruction.
#17
Robert Millikan used Stokes' Law and terminal velocity measurements of falling charged oil drops in 1909 to calculate the elementary electric charge.
#18
In a vacuum, where fluid drag is completely absent, objects experience constant acceleration due to gravity and never reach a terminal velocity.
#19
Sedimentation velocity in centrifugation applies Stokes' Law by substituting artificial centrifugal acceleration for gravitational acceleration.
#20
In planetary atmospheres, terminal velocity varies with altitude because atmospheric density decreases exponentially with height.
Subject Specialist Commentary
Analytical perspective & practical exam advice from the Master10 academic board
When an object drops through the air, gravity pulls it downward with increasing speed, but rushing air pushes back with growing resistance. Eventually, the upward air drag exactly matches the downward pull of gravity. At that instant of force equilibrium, acceleration stops completely, and the object coasts downward at a steady, maximum speed known as terminal velocity.
Competitive exams frequently set traps regarding acceleration at terminal velocity: remember that acceleration is zero meters per second squared, not gravitational acceleration. In formula-based questions for UPSC and SSC, distinguish high-speed aerodynamic drag, where terminal speed depends on the square root of mass over area, from Stokes' law for microscopic spheres, where terminal velocity is directly proportional to the square of the radius.
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